x^2+(2sqrt(5))x+5=0

解

x^{2} + (25) x + 5 = 0

x = - 5

十進法表記

x = - 2.23606 \dots

解答ステップ

x^{2} + (25) x + 5 = 0

改良

x^{2} + 25 x + 5 = 0

解くとthe二次式

x_{1, 2} = \frac{- 2 5 \pm ( 2 5 ) ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

(25)^{2} - 4 \cdot 1 \cdot 5 = 0

x_{1, 2} = \frac{- 2 5 \pm 0}{2 \cdot 1}

x = \frac{- 2 5}{2 \cdot 1}

\frac{- 2 5}{2 \cdot 1} = - 5

x = - 5

二次equationの解:

x = - 5