en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

|2u+5|<= 7

Solution

∣ 2 u + 5 ∣ \leq 7

Solution

- 6 \leq u \leq 1

+1

Interval Notation

[- 6, 1]

Solution steps

∣ 2 u + 5 ∣ \leq 7

Apply absolute rule: If

∣ u ∣ \leq a, a > 0

then

- a \leq u \leq a

- 7 \leq 2 u + 5 \leq 7

2 u + 5 \geq - 7 and 2 u + 5 \leq 7

u \geq - 6 and u \leq 1

Merge Overlapping Intervals

- 6 \leq u \leq 1

Popular Examples

5/2 x+(x-4)/2 =11

\frac{5}{2} x + \frac{x - 4}{2} = 11

simplify-4/3-1 simplify

- \frac{4}{3} - 1

x^2+8/7+15/49 =0

x^{2} + \frac{8}{7} + \frac{15}{49} = 0

3 (2 x - 3) < 27

simplify (-1/3)(-5/2)(-3/10)simplify

(- \frac{1}{3}) (- \frac{5}{2}) (- \frac{3}{10})

Frequently Asked Questions (FAQ)

What is |2u+5|<= 7 ?
The solution to |2u+5|<= 7 is -6<= u<= 1