-3a^2-15a+252=0

解

- 3 a^{2} - 15 a + 252 = 0

a = - 12, a = 7

解答ステップ

- 3 a^{2} - 15 a + 252 = 0

解くとthe二次式

a_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 ( - 3 ) \cdot 252}{2 ( - 3 )}

(- 15)^{2} - 4 (- 3) \cdot 252 = 57

a_{1, 2} = \frac{- ( - 15 ) \pm 57}{2 ( - 3 )}

解を分離する

a_{1} = \frac{- ( - 15 ) + 57}{2 ( - 3 )}, a_{2} = \frac{- ( - 15 ) - 57}{2 ( - 3 )}

a = \frac{- ( - 15 ) + 57}{2 ( - 3 )} : - 12

a = \frac{- ( - 15 ) - 57}{2 ( - 3 )} : 7

二次equationの解:

a = - 12, a = 7