80x+1/2 (4)x^2-1000=0

解

80 x + \frac{1}{2} (4) x^{2} - 1000 = 0

x = 10, x = - 50

解答ステップ

80 x + \frac{1}{2} (4) x^{2} - 1000 = 0

以下で両辺を乗じる:

2

4 x^{2} + 160 x - 2000 = 0

解くとthe二次式

x_{1, 2} = \frac{- 160 \pm 16 0 ^{2} - 4 \cdot 4 ( - 2000 )}{2 \cdot 4}

16 0^{2} - 4 \cdot 4 (- 2000) = 240

x_{1, 2} = \frac{- 160 \pm 240}{2 \cdot 4}

解を分離する

x_{1} = \frac{- 160 + 240}{2 \cdot 4}, x_{2} = \frac{- 160 - 240}{2 \cdot 4}

x = \frac{- 160 + 240}{2 \cdot 4} : 10

x = \frac{- 160 - 240}{2 \cdot 4} : - 50

二次equationの解:

x = 10, x = - 50