What are the solutions to the equation 2x^2-7x-2=0 ?

The solutions to the equation 2x^2-7x-2=0 are x=(7+sqrt(65))/4 ,x=(7-sqrt(65))/4

Find the zeros of 2x^2-7x-2=0

The zeros of 2x^2-7x-2=0 are x=(7+sqrt(65))/4 ,x=(7-sqrt(65))/4

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2 x^{2} - 7 x - 2 = 0

x = \frac{7 + 65}{4}, x = \frac{7 - 65}{4}

Decimal Notation

x = 3.76556 \dots, x = - 0.26556 \dots

Solution steps

2 x^{2} - 7 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 2 ( - 2 )}{2 \cdot 2}

(- 7)^{2} - 4 \cdot 2 (- 2) = 65

x_{1, 2} = \frac{- ( - 7 ) \pm 65}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 65}{2 \cdot 2}, x_{2} = \frac{- ( - 7 ) - 65}{2 \cdot 2}

x = \frac{- ( - 7 ) + 65}{2 \cdot 2} : \frac{7 + 65}{4}

x = \frac{- ( - 7 ) - 65}{2 \cdot 2} : \frac{7 - 65}{4}

The solutions to the quadratic equation are:

x = \frac{7 + 65}{4}, x = \frac{7 - 65}{4}

2 (6 v + 9) > 5 v + 4

6 - 9

(8)^{\frac{1}{3}}

75 - 418 + 232

What are the solutions to the equation 2x^2-7x-2=0 ?
The solutions to the equation 2x^2-7x-2=0 are x=(7+sqrt(65))/4 ,x=(7-sqrt(65))/4
Find the zeros of 2x^2-7x-2=0
The zeros of 2x^2-7x-2=0 are x=(7+sqrt(65))/4 ,x=(7-sqrt(65))/4