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受欢迎的代数 >

a=(2bx)/(1+b(x-1))

解答

a = \frac{2 b x}{1 + b ( x - 1 )}

解答

x = \frac{- a + ab}{b ( - 2 + a )}; a \neq = 2

求解步骤

a = \frac{2 b x}{1 + b ( x - 1 )}

在两边乘以

1 + b (x - 1)

a (1 + b (x - 1)) = 2 b x

展开

a (1 + b (x - 1)) : a + ab x - ab

a + ab x - ab = 2 b x

将

a

到右边

ab x - ab = 2 b x - a

将

ab

到右边

ab x = 2 b x - a + ab

将

2 b x

para o lado esquerdo

ab x - 2 b x = - a + ab

分解

ab x - 2 b x : b x (a - 2)

b x (a - 2) = - a + ab

两边除以

b (a - 2); a \neq = 2

x = \frac{- a + ab}{b ( - 2 + a )}; a \neq = 2

作图

流行的例子

(x^3-3x^2)/(x-3)=6x-9

\frac{x ^{3} - 3 x ^{2}}{x - 3} = 6 x - 9

1/(x-1)= 3/(2x+3)

\frac{1}{x - 1} = \frac{3}{2 x + 3}

(x-7)/(x-4)= 2/x

\frac{x - 7}{x - 4} = \frac{2}{x}

solvefor x,(x+y)/(x-y)=a

so l v e f or x, \frac{x + y}{x - y} = a

solvefor x,(x+y)/(x-y)=5

so l v e f or x, \frac{x + y}{x - y} = 5