pi^{1-x}=e^x

Lösung

π^{1 - x} = e^{x}

x = \frac{ln ( π )}{ln ( π ) + 1}

Dezimale

x = 0.53374 \dots

Schritte zur Lösung

π^{1 - x} = e^{x}

Wende Exponentenregel an

(1 - x) ln (π) = x

Löse

(1 - x) ln (π) = x : x = \frac{ln ( π )}{ln ( π ) + 1}

x = \frac{ln ( π )}{ln ( π ) + 1}

4^{x} + 4^{- x} = \frac{5}{2}

2^{x} + 2^{1 - x} = 3

2^{x} = \frac{1}{16}

10 0^{x - 1} = 100 0^{2 x}

4^{x} = 1