5^{x+2}=7^{x-2}

Lösung

5^{x + 2} = 7^{x - 2}

x = \frac{2 ln ( 35 )}{ln ( 7 ) - ln ( 5 )}

Dezimale

x = 21.13308 \dots

Schritte zur Lösung

5^{x + 2} = 7^{x - 2}

Wende Exponentenregel an

(x + 2) ln (5) = (x - 2) ln (7)

Löse

(x + 2) ln (5) = (x - 2) ln (7) : x = \frac{2 ln ( 35 )}{ln ( 7 ) - ln ( 5 )}

x = \frac{2 ln ( 35 )}{ln ( 7 ) - ln ( 5 )}

e^{- 0.05 x} = 0.01

9^{x} = \frac{1}{81}

5^{3 x + 7} = 2 5^{x - 4}

9^{x} - 10 \cdot 3^{x} + 9 = 0

so l v e f or t, A = P (1 + r)^{t}