solvefor a,e^{ax}=1+x^2

Lösung

löse nach

a, e^{a x} = 1 + x^{2}

a = \frac{ln ( 1 + x ^{2} )}{x}

Schritte zur Lösung

e^{a x} = 1 + x^{2}

Wende Exponentenregel an

a x = ln (1 + x^{2})

Löse

a x = ln (1 + x^{2}) : a = \frac{ln ( 1 + x ^{2} )}{x}

a = \frac{ln ( 1 + x ^{2} )}{x}

e^{x} - x - 1 = 0

3 6^{x} = 216

3^{x + 2} = 243

3 = 2^{x - 5}

2 (3^{2 x}) - 5 (3^{x}) + 2 = 0