3*3^x=27^{2x}

Lösung

3 \cdot 3^{x} = 2 7^{2 x}

x = \frac{1}{5}

Dezimale

x = 0.2

Schritte zur Lösung

3 \cdot 3^{x} = 2 7^{2 x}

Wende Exponentenregel an

x + 1 = 6 x

Löse

x + 1 = 6 x : x = \frac{1}{5}

x = \frac{1}{5}

3 (2^{x - 3}) = 6^{x - 1}

9^{x - 10} = 1

5^{2 x + 1} - 24 (5^{x}) - 5 = 0

so l v e f or x, e^{2 x} = 4

e^{x^{2} - 3} = e^{2 x}