e^{x+1}=9^{(2x)/3}

Lösung

e^{x + 1} = 9^{\frac{2 x}{3}}

x = \frac{3}{4 ln ( 3 ) - 3}

Dezimale

x = 2.15138 \dots

Schritte zur Lösung

e^{x + 1} = 9^{\frac{2 x}{3}}

Wende Exponentenregel an

x + 1 = \frac{2 x}{3} ln (9)

Löse

x + 1 = \frac{2 x}{3} ln (9) : x = \frac{3}{4 ln ( 3 ) - 3}

x = \frac{3}{4 ln ( 3 ) - 3}

e^{- x} - 2 x e^{x} = 0

5^{x} + 5^{x + 1} = 750

(\frac{1}{8})^{x} = 1 6^{x - 3}

(0.5)^{x} = 2

e^{t} = 1