8^{6x^2+4x}=4^{9x^2-9x+6}

Lösung

8^{6 x^{2} + 4 x} = 4^{9 x^{2} - 9 x + 6}

x = \frac{2}{5}

Dezimale

x = 0.4

Schritte zur Lösung

8^{6 x^{2} + 4 x} = 4^{9 x^{2} - 9 x + 6}

Wende Exponentenregel an

3 (6 x^{2} + 4 x) = 2 (9 x^{2} - 9 x + 6)

Löse

3 (6 x^{2} + 4 x) = 2 (9 x^{2} - 9 x + 6) : x = \frac{2}{5}

x = \frac{2}{5}

0. 1^{x} = 10

so l v e f or n, (1 + i)^{n} = 32 i

2^{x} = 46

(e^{2})^{3 x} = e^{2 x} e^{3 x}

2^{x} = 30