(e^{4x+1})^3=e^2

Lösung

(e^{4 x + 1})^{3} = e^{2}

x = - \frac{1}{12}

Dezimale

x = - 0.08333 \dots

Schritte zur Lösung

(e^{4 x + 1})^{3} = e^{2}

Wende Exponentenregel an

(4 x + 1) \cdot 3 = 2

Löse

(4 x + 1) \cdot 3 = 2 : x = - \frac{1}{12}

x = - \frac{1}{12}

65 = 1 5^{x}

62 5^{x + 5} = 5^{3 x - 4} 2 5^{2 x - 3}

8 1^{x^{2} - 1} = 27

2^{3 x} = \frac{1}{16}

so l v e f or x, 2^{x} = 1