432=3^{x+1}*2^{2x}

Lösung

432 = 3^{x + 1} \cdot 2^{2 x}

x = 2

Schritte zur Lösung

432 = 3^{x + 1} \cdot 2^{2 x}

Wende Exponentenregel an

ln (432) = (lo g_{2} (3) (x + 1) + 2 x) ln (2)

Löse

ln (432) = (lo g_{2} (3) (x + 1) + 2 x) ln (2) : x = 2

x = 2

1 5^{3 x - 2} = 1 3^{3 x - 2}

e^{x + 3} = \frac{1}{e}

3^{2 x + 1} = 2 7^{x}

2^{x} = 100000

2^{x^{2} - 5 x} = 4^{x - 5}