2^{x^2-2x+1}=1

Lösung

2^{x^{2} - 2 x + 1} = 1

x = 1

Schritte zur Lösung

2^{x^{2} - 2 x + 1} = 1

Wende Exponentenregel an

(x^{2} - 2 x + 1) ln (2) = ln (1)

Löse

(x^{2} - 2 x + 1) ln (2) = ln (1) : x = 1

x = 1

3 \cdot 2^{x + 2} - 5 \cdot 2^{x} = 56

e^{x + 1} = 3

2 \cdot 1 0^{9 a} = 29

\frac{8 ^{m + 3}}{2 ^{2}} = 2^{4 m}

5^{9^{x}} = 12 5^{3^{x + 4}}