20^b=4

Lösung

2 0^{b} = 4

b = \frac{2 ln ( 2 )}{ln ( 20 )}

Dezimale

b = 0.46275 \dots

Schritte zur Lösung

2 0^{b} = 4

Wende Exponentenregel an

b ln (20) = ln (4)

Löse

b ln (20) = ln (4) : b = \frac{2 ln ( 2 )}{ln ( 20 )}

b = \frac{2 ln ( 2 )}{ln ( 20 )}

1240000 = 525600 e^{0.03 (t)}

e^{l n (x + 1)} = 3

2^{1 - x} + 2^{1 + x} = 4

\frac{( 5000000 )}{2 ^{n}} = 1

2 (3)^{x} = 34