8^{3x+1}=128^{x-2}

Lösung

8^{3 x + 1} = 12 8^{x - 2}

x = - \frac{17}{2}

Dezimale

x = - 8.5

Schritte zur Lösung

8^{3 x + 1} = 12 8^{x - 2}

Wende Exponentenregel an

3 (3 x + 1) = 7 (x - 2)

Löse

3 (3 x + 1) = 7 (x - 2) : x = - \frac{17}{2}

x = - \frac{17}{2}

7^{x - 4} = 7^{8}

2^{3 - 8 w} = 18

8^{x + 1} - 8^{x - 1} = 20

71 = 2 1^{x}

5^{2 x} = 5^{x} + 30