4^{3-2x}=12

Lösung

4^{3 - 2 x} = 12

x = \frac{ln ( \frac{16}{3} )}{4 ln ( 2 )}

Dezimale

x = 0.60375 \dots

Schritte zur Lösung

4^{3 - 2 x} = 12

Wende Exponentenregel an

(3 - 2 x) ln (4) = ln (12)

Löse

(3 - 2 x) ln (4) = ln (12) : x = \frac{ln ( \frac{16}{3} )}{4 ln ( 2 )}

x = \frac{ln ( \frac{16}{3} )}{4 ln ( 2 )}

4^{4 x - 1} = \frac{1}{2}

4^{3 x + 5} = 8^{4 x - 3}

3^{x} - 12 + 27 \cdot 3^{- x} = 0

9^{4 x} = \frac{1}{27}

3^{x^{2}} \cdot 3 = 3