4^{x-3}=(1/8)^{2x+1}

Lösung

4^{x - 3} = (\frac{1}{8})^{2 x + 1}

x = \frac{3}{8}

Dezimale

x = 0.375

Schritte zur Lösung

4^{x - 3} = (\frac{1}{8})^{2 x + 1}

Wende Exponentenregel an

2 (x - 3) = - 3 (2 x + 1)

Löse

2 (x - 3) = - 3 (2 x + 1) : x = \frac{3}{8}

x = \frac{3}{8}

6 4^{1 - 2 x} = 0.2 5^{3 x}

4^{1 - x} + 2^{3 - x} - 12 = 0

x = 2^{\frac{x}{2}}

3^{5 x - 1} = 5^{2 x}

8^{x} = 132