(4^{5x+1})=16

Lösung

(4^{5 x + 1}) = 16

x = \frac{1}{5}

Dezimale

x = 0.2

Schritte zur Lösung

(4^{5 x + 1}) = 16

Wende Exponentenregel an

5 x + 1 = 2

Löse

5 x + 1 = 2 : x = \frac{1}{5}

x = \frac{1}{5}

so l v e f or i, \frac{n}{2 ^{i}} = 1

so l v e f or x, y - 3 = 4 (5^{2 x + 1})

57 = 1 3^{x}

2^{6 \cdot l o g_{4} (x)} = 8

e^{2 x + 1} = \frac{1}{e}