9^x=27^{x+1}

Lösung

9^{x} = 2 7^{x + 1}

x = - 3

Schritte zur Lösung

9^{x} = 2 7^{x + 1}

Wende Exponentenregel an

2 x = 3 (x + 1)

Löse

2 x = 3 (x + 1) : x = - 3

x = - 3

2^{x^{2} - 3} = 4^{x}

2 x + 1 = 2^{x}

3^{2 7^{x - 2}} = 9^{9^{x + 1}}

2 = (\frac{1}{4})^{x}

57 = 5 e^{0.02 \cdot x}