8^{x-3}=4^{3x-1}

Lösung

8^{x - 3} = 4^{3 x - 1}

x = - \frac{7}{3}

Dezimale

x = - 2.33333 \dots

Schritte zur Lösung

8^{x - 3} = 4^{3 x - 1}

Wende Exponentenregel an

3 (x - 3) = 2 (3 x - 1)

Löse

3 (x - 3) = 2 (3 x - 1) : x = - \frac{7}{3}

x = - \frac{7}{3}

e^{3 x - 2} = 1

so l v e f or x, e^{- 0.78 x} = 0.03

5^{x + 5} = 125

0. 1^{x} = 100

e^{4 x} = 15