2^{x-1}=3^{2x-1}

Lösung

2^{x - 1} = 3^{2 x - 1}

x = \frac{ln ( 3 ) - ln ( 2 )}{2 ln ( 3 ) - ln ( 2 )}

Dezimale

x = 0.26957 \dots

Schritte zur Lösung

2^{x - 1} = 3^{2 x - 1}

Wende Exponentenregel an

(x - 1) ln (2) = (2 x - 1) ln (3)

Löse

(x - 1) ln (2) = (2 x - 1) ln (3) : x = \frac{ln ( 3 ) - ln ( 2 )}{2 ln ( 3 ) - ln ( 2 )}

x = \frac{ln ( 3 ) - ln ( 2 )}{2 ln ( 3 ) - ln ( 2 )}

so l v e f or y, (\frac{1}{2})^{y} = x

1 6^{x} - 5 \cdot 4^{x} = 24

3^{2 c + 1} = 28 \cdot 3^{c} - 9

9^{x^{2} - x - 4} = 3^{6 x + 2}

2^{2 x} + 2^{x} = 12