7^{(x+2)}=98

Lösung

7^{(x + 2)} = 98

x = \frac{ln ( 98 )}{ln ( 7 )} - 2

Dezimale

x = 0.35620 \dots

Schritte zur Lösung

7^{(x + 2)} = 98

Wende Exponentenregel an

(x + 2) ln (7) = ln (98)

Löse

(x + 2) ln (7) = ln (98) : x = \frac{ln ( 98 )}{ln ( 7 )} - 2

x = \frac{ln ( 98 )}{ln ( 7 )} - 2

so l v e f or x, e^{x} - y = 0

1 6^{x + 2} = \frac{1}{4}

(x - 2)^{x^{2} - 2 x} = (x - 2)^{x + 4}

7^{5 x - 4} = 14

2^{2 x} = n + 1