2e^{2x}=e^{-x}

Lösung

2 e^{2 x} = e^{- x}

x = - \frac{ln ( 2 )}{3}

Dezimale

x = - 0.23104 \dots

Schritte zur Lösung

2 e^{2 x} = e^{- x}

Wende Exponentenregel an

ln (2) + 2 x = - x

Löse

ln (2) + 2 x = - x : x = - \frac{ln ( 2 )}{3}

x = - \frac{ln ( 2 )}{3}

e^{x - 5} = 15

(\frac{1}{2})^{n} = 4^{n + 1}

2^{x} + 4^{x} = 1056

2 = (1 + \frac{0.06}{0.5})^{0.5 n}

26 = 220 (0.5)^{\frac{x}{6}}