(1/4)^{x-1}=16^{x+2}

Lösung

(\frac{1}{4})^{x - 1} = 1 6^{x + 2}

x = - 1

Schritte zur Lösung

(\frac{1}{4})^{x - 1} = 1 6^{x + 2}

Wende Exponentenregel an

- (x - 1) = 2 (x + 2)

Löse

- (x - 1) = 2 (x + 2) : x = - 1

x = - 1

0 = x^{2} e^{- x^{2}}

2^{x} = 41

2^{x} = 80

2^{x} = 70

\frac{1}{e ^{x}} = e^{x}