2^{x+1}=3^{2x+1}

Lösung

2^{x + 1} = 3^{2 x + 1}

x = \frac{ln ( 3 ) - ln ( 2 )}{ln ( 2 ) - 2 ln ( 3 )}

Dezimale

x = - 0.26957 \dots

Schritte zur Lösung

2^{x + 1} = 3^{2 x + 1}

Wende Exponentenregel an

(x + 1) ln (2) = (2 x + 1) ln (3)

Löse

(x + 1) ln (2) = (2 x + 1) ln (3) : x = \frac{ln ( 3 ) - ln ( 2 )}{ln ( 2 ) - 2 ln ( 3 )}

x = \frac{ln ( 3 ) - ln ( 2 )}{ln ( 2 ) - 2 ln ( 3 )}

2^{2 - 3 x} - 8^{x} = - 3

4^{x} - 4^{x - 1} = 6

3^{2 y + 3} = 27

3 6^{2 x - 1} = 6^{3}

4^{x - 1} = (\frac{1}{4})^{2 x}