2=e^{k^{12}}

Lösung

2 = e^{k^{12}}

k = 12 ln (2), k = - 12 ln (2)

Dezimale

k = 0.96991 \dots, k = - 0.96991 \dots

Schritte zur Lösung

2 = e^{k^{12}}

Wende Exponentenregel an

ln (2) = k^{12}

Löse

ln (2) = k^{12} : k = 12 ln (2), k = - 12 ln (2)

k = 12 ln (2), k = - 12 ln (2)

62 5^{2 y - 3} = 25

2 7^{n^{2}} = 9^{5 n - 4}

7^{12 x} = 7^{2 x - 2}

8^{2 x} = \frac{1}{64}

25 6^{x} = 0.25