2(3^{(2x-1)})=4^{(x+1)}

Lösung

2 (3^{(2 x - 1)}) = 4^{(x + 1)}

x = \frac{ln ( 6 )}{2 ( ln ( 3 ) - ln ( 2 ) )}

Dezimale

x = 2.20951 \dots

Schritte zur Lösung

2 (3^{(2 x - 1)}) = 4^{(x + 1)}

Wende Exponentenregel an

ln (2) + (2 x - 1) ln (3) = (x + 1) ln (4)

Löse

ln (2) + (2 x - 1) ln (3) = (x + 1) ln (4) : x = \frac{ln ( 6 )}{2 ( ln ( 3 ) - ln ( 2 ) )}

x = \frac{ln ( 6 )}{2 ( ln ( 3 ) - ln ( 2 ) )}

5^{x^{2}} = 5

1 0^{2 x - 3} = 1000

so l v e f or x, 3^{4 x + 1} = 27

7^{- 2 x + 9} = 608

5^{x - 1} = 2 5^{- x + 2}