4^{2x+1}*5^{x-2}=6^{1-x}

Lösung

4^{2 x + 1} \cdot 5^{x - 2} = 6^{1 - x}

x = \frac{ln ( \frac{75}{2} )}{ln ( 480 )}

Dezimale

x = 0.58705 \dots

Schritte zur Lösung

4^{2 x + 1} \cdot 5^{x - 2} = 6^{1 - x}

Wende Exponentenregel an

(2 x + 1 + lo g_{4} (5) (x - 2)) ln (4) = (1 - x) ln (6)

Löse

(2 x + 1 + lo g_{4} (5) (x - 2)) ln (4) = (1 - x) ln (6) : x = \frac{ln ( \frac{75}{2} )}{ln ( 480 )}

x = \frac{ln ( \frac{75}{2} )}{ln ( 480 )}

x 9 = 8 + x + e^{x}

8^{- 9^{x^{- 1}}} = \frac{1}{2}

1.005 7^{4 t} = 2.22717

4^{2 x - 6} = 48

432 = 2^{4} \cdot 3^{x}