7^{3x+2}=140

Lösung

7^{3 x + 2} = 140

x = \frac{ln ( \frac{20}{7} )}{3 ln ( 7 )}

Dezimale

x = 0.17983 \dots

Schritte zur Lösung

7^{3 x + 2} = 140

Wende Exponentenregel an

(3 x + 2) ln (7) = ln (140)

Löse

(3 x + 2) ln (7) = ln (140) : x = \frac{ln ( \frac{20}{7} )}{3 ln ( 7 )}

x = \frac{ln ( \frac{20}{7} )}{3 ln ( 7 )}

4^{- 0.2 x} + 1 = 0

1 6^{(x^{2})} = 4^{6 x - 4}

1.5 = e^{k \cdot \frac{1}{2}}

e^{5 x} = e^{10 x}

44000 = 26000 (1.02)^{x (4)}, x