(sqrt(3))^{3-x}=9^{x+2}

Lösung

(3)^{3 - x} = 9^{x + 2}

x = - 1

Schritte zur Lösung

(3)^{3 - x} = 9^{x + 2}

Wende Exponentenregel an

\frac{1}{2} (3 - x) = 2 (x + 2)

Löse

\frac{1}{2} (3 - x) = 2 (x + 2) : x = - 1

x = - 1

2^{n} = 16

e^{x} + 5 = 0

so l v e f or x, 5^{8 x} = 8^{8 x - 5}

75 = 3 3^{x}

4^{x} = 3 (2)^{x}