3^x=9^{2x-1}

Lösung

3^{x} = 9^{2 x - 1}

x = \frac{2}{3}

Dezimale

x = 0.66666 \dots

Schritte zur Lösung

3^{x} = 9^{2 x - 1}

Wende Exponentenregel an

x = 2 (2 x - 1)

Löse

x = 2 (2 x - 1) : x = \frac{2}{3}

x = \frac{2}{3}

3^{7 x} = 3.3

\frac{1}{3} \cdot 2^{x} = 12

3^{x + 1} - 4 + \frac{1}{3 ^{x}} = 0

1 0^{x} = 22.4

2^{2 x - 1} = 2^{2 x} + 2^{- 1}