faktorisieren x^4+6x-7

Lösung

faktorisieren

x^{4} + 6 x - 7

(x - 1) (x^{3} + x^{2} + x + 7)

Schritte zur Lösung

x^{4} + 6 x - 7

Wende den rationalen Nullstellentest an

= (x - 1) \frac{x ^{4} + 6 x - 7}{x - 1}

\frac{x ^{4} + 6 x - 7}{x - 1} = x^{3} + x^{2} + x + 7

= (x - 1) (x^{3} + x^{2} + x + 7)

s im pl i f y \frac{9 x ^{5} y ^{2}}{6 x ^{8} y ^{4}}

f a c t or (3 x^{2} - 12 x) (x^{2} - 2 x + 1)

f a c t or a (x + 1) - b (x + 1) + c (x + 1)

s im pl i f y \frac{1}{10} \cdot \frac{1}{2}

10 n^{2} + 2 = 292