3^{2x}=7^{2x-1}

Lösung

3^{2 x} = 7^{2 x - 1}

x = - \frac{ln ( 7 )}{2 ( ln ( 3 ) - ln ( 7 ) )}

Dezimale

x = 1.14830 \dots

Schritte zur Lösung

3^{2 x} = 7^{2 x - 1}

Wende Exponentenregel an

2 x ln (3) = (2 x - 1) ln (7)

Löse

2 x ln (3) = (2 x - 1) ln (7) : x = - \frac{ln ( 7 )}{2 ( ln ( 3 ) - ln ( 7 ) )}

x = - \frac{ln ( 7 )}{2 ( ln ( 3 ) - ln ( 7 ) )}

1.007 5^{x} = 1.251445278

5 \cdot e^{x} = 18

7.01 = 3^{2 x} - 2.4

so l v e f or x, y = 1.0251 e^{- 0.418 x}

e^{- \frac{10}{x}} = 1