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受欢迎的代数 >

((x-1)(x+2)}{12}-\frac{(x+1)(x-2))/6-1=(x-3)/3

解答

\frac{( x - 1 ) \cdot ( x + 2 )}{12} - \frac{( x + 1 ) \cdot ( x - 2 )}{6} - 1 = \frac{x - 3}{3}

解答

x = - 2, x = 1

求解步骤

\frac{( x - 1 ) ( x + 2 )}{12} - \frac{( x + 1 ) ( x - 2 )}{6} - 1 = \frac{x - 3}{3}

找到

12, 6, 3

的最小公倍数:

12

乘以最小公倍数=

12

\frac{( x - 1 ) ( x + 2 )}{12} \cdot 12 - \frac{( x + 1 ) ( x - 2 )}{6} \cdot 12 - 1 \cdot 12 = \frac{x - 3}{3} \cdot 12

化简

(x - 1) (x + 2) - 2 (x + 1) (x - 2) - 12 = 4 (x - 3)

展开

(x - 1) (x + 2) - 2 (x + 1) (x - 2) - 12 : - x^{2} + 3 x - 10

展开

4 (x - 3) : 4 x - 12

- x^{2} + 3 x - 10 = 4 x - 12

将

12

para o lado esquerdo

- x^{2} + 3 x + 2 = 4 x

将

4 x

para o lado esquerdo

- x^{2} - x + 2 = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 ( - 1 ) \cdot 2}{2 ( - 1 )}

(- 1)^{2} - 4 (- 1) \cdot 2 = 3

x_{1, 2} = \frac{- ( - 1 ) \pm 3}{2 ( - 1 )}

将解分隔开

x_{1} = \frac{- ( - 1 ) + 3}{2 ( - 1 )}, x_{2} = \frac{- ( - 1 ) - 3}{2 ( - 1 )}

x = \frac{- ( - 1 ) + 3}{2 ( - 1 )} : - 2

x = \frac{- ( - 1 ) - 3}{2 ( - 1 )} : 1

二次方程组的解是:

x = - 2, x = 1

作图

流行的例子

化简 1/(12m^3n)+8/(22m^2n^2)

s im pl i f y \frac{1}{12 m ^{3} n} + \frac{8}{22 m ^{2} n ^{2}}

化简 3(4c+1)-4(4c-3)

s im pl i f y 3 (4 c + 1) - 4 (4 c - 3)

化简 (4/9)^{1/2}

s im pl i f y (\frac{4}{9})^{\frac{1}{2}}

因式分解 x(a-7)-y(a-7)

f a c t or x (a - 7) - y (a - 7)

-3<= 3x+7<= 1/2

- 3 \leq 3 x + 7 \leq \frac{1}{2}