m^3=125

Lösung

m^{3} = 125

m = 5, m = - \frac{5}{2} + \frac{5 3}{2} i, m = - \frac{5}{2} - \frac{5 3}{2} i

Schritte zur Lösung

m^{3} = 125

Für

x^{3} = f (a)

sind die Lösungen

x = 3 f (a), 3 f (a) \frac{- 1 - 3 i}{2}, 3 f (a) \frac{- 1 + 3 i}{2}

m = 3125, m = 3125 \frac{- 1 + 3 i}{2}, m = 3125 \frac{- 1 - 3 i}{2}

3125 = 5

Vereinfache

3125 \frac{- 1 + 3 i}{2} : - \frac{5}{2} + \frac{5 3}{2} i

Vereinfache

3125 \frac{- 1 - 3 i}{2} : - \frac{5}{2} - \frac{5 3}{2} i

m = 5, m = - \frac{5}{2} + \frac{5 3}{2} i, m = - \frac{5}{2} - \frac{5 3}{2} i

5 x^{3} - 3 x - 1 = 0

16 x^{4} = 1048576

- (a + 1)^{2} (a - 8) = 0

x^{2} + 6 x + 9 = 4 x^{4}

1400 = 700 (1 + \frac{x}{100})^{5}