log_{1/2}(2x+1)=-10

解答

lo g_{\frac{1}{2}} (2 x + 1) = - 10

x = \frac{1023}{2}

十进制

x = 511.5

求解步骤

lo g_{\frac{1}{2}} (2 x + 1) = - 10

使用对数运算法则

2 x + 1 = 1024

解

2 x + 1 = 1024 : x = \frac{1023}{2}

x = \frac{1023}{2}

lo g_{10} (a) = 2.655

lo g_{10} (x) = 1.6

lo g_{6} (x + 5) = 2

lo g_{a} (a) = 1

612733 = 48484 \cdot ln (x) + 67854