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Beliebt Algebra >

log_{3}(2x+1)=-1

Lösung

lo g_{3} (2 x + 1) = - 1

Lösung

x = - \frac{1}{3}

+1

Dezimale

x = - 0.33333 \dots

Schritte zur Lösung

lo g_{3} (2 x + 1) = - 1

Wende die log Regel an

2 x + 1 = \frac{1}{3}

Löse

2 x + 1 = \frac{1}{3} : x = - \frac{1}{3}

x = - \frac{1}{3}

Graph

Beliebte Beispiele

log_{a}(32)=-5/2

lo g_{a} (32) = - \frac{5}{2}

3.5=-log_{10}(c)

3.5 = - lo g_{10} (c)

log_{3}(1+log_{3}(2x-7))=1

lo g_{3} (1 + lo g_{3} (2 x - 7)) = 1

log_{5}(x^2+10x+1)=2

lo g_{5} (x^{2} + 10 x + 1) = 2

log_{2}(x-4)+log_{2}(x+3)=3

lo g_{2} (x - 4) + lo g_{2} (x + 3) = 3