log_{10}(x)=2.952

Lösung

lo g_{10} (x) = 2.952

x = 1 0^{2.952}

Dezimale

x = 895.36476 \dots

Schritte zur Lösung

lo g_{10} (x) = 2.952

Wende die log Regel an

x = 1 0^{2.952}

15 = 10 lo g_{10} (x)

2 ln (x) = ln (x^{4}) - ln (8)

lo g_{4} (x) = 1.5

ln (x + 1) = 4

lo g_{2} (5 x) - 3 lo g_{2} (7) = 0