solvefor x,0=ln(1-y^2-x)

Lösung

löse nach

x, 0 = ln (1 - y^{2} - x)

x = - y^{2}

Schritte zur Lösung

0 = ln (1 - y^{2} - x)

Wende die log Regel an

1 = 1 - y^{2} - x

Löse

1 = 1 - y^{2} - x : x = - y^{2}

x = - y^{2}

3.9 = ln (\frac{( k - x )}{x})

ln (4) + 2 ln (5) = ln (x)

0 = lo g_{3} (x + 1) - 2

ln (x) = m - 1

3 ln (3 x + 9) + 19 = 13