log_{2}((r+4)^2)=6

Lösung

lo g_{2} ((r + 4)^{2}) = 6

r = 4, r = - 12

Schritte zur Lösung

lo g_{2} ((r + 4)^{2}) = 6

Wende die log Regel an

(r + 4)^{2} = 64

Löse

(r + 4)^{2} = 64 : r = 4, r = - 12

r = 4, r = - 12

ln (x) + 2 x - 2 = 0

50 = 9.4177 ln (x) + 59.156

so l v e f or x, ln (y) - ln (x) = C

so l v e f or y, x = 3 ln (y - 2)

1 = lo g_{64} (x)