ln(4x-1)=2

Lösung

ln (4 x - 1) = 2

x = \frac{e ^{2} + 1}{4}

Dezimale

x = 2.09726 \dots

Schritte zur Lösung

ln (4 x - 1) = 2

Wende die log Regel an

4 x - 1 = e^{2}

Löse

4 x - 1 = e^{2} : x = \frac{e ^{2} + 1}{4}

x = \frac{e ^{2} + 1}{4}

lo g_{4} (4 x) - lo g_{4} (x - 6) = 2

ln (x) = - 4.3178

x = ln (3.2 x 1 0^{4})

lo g_{2} (x) - 8 lo g_{10} (x) + 15 = 0

ln ∣ x ∣ - x = 0