(x+n)/(2ln(x)-n)=0

解

\frac{x + n}{2 ln ( x ) - n} = 0

x = - n {n < - 2 W_{0} (\frac{1}{2}) or - 2 W_{0} (\frac{1}{2}) < n < 0}

解答ステップ

\frac{x + n}{2 ln ( x ) - n} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

x + n = 0

x

を右側に移動します

n = - x

解く

n = - x : x = - n

x = - n

解を検算する:

x = - n {n < - 2 W_{0} (\frac{1}{2}) or - 2 W_{0} (\frac{1}{2}) < n < 0}

解は

x = - n {n < - 2 W_{0} (\frac{1}{2}) or - 2 W_{0} (\frac{1}{2}) < n < 0}