(2+3i)x-(1+i)y=3+4i

解答

(2 + 3 i) x - (1 + i) y = 3 + 4 i

x = 1, y = - 1

求解步骤

(2 + 3 i) x - (1 + i) y = 3 + 4 i

将

(2 + 3 i) x - (1 + i) y

改写成标准复数形式:

(2 x - y) + (3 x - y) i

(2 x - y) + (3 x - y) i = 3 + 4 i

复数仅在实部和虚部均相等时才相等改写为方程组:

[2 x - y = 3 3 x - y = 4]

[2 x - y = 3 3 x - y = 4] : x = 1, y = - 1

x = 1, y = - 1

a - bi = ai - b

p = i v

a (1 + 2 i) + b (2 - 3 i) = 5 + 3 i

- 4 i + 4 y - 8 = - 2 + x i + 5 x

z^{2} + (5 + 6 i) z - 3 + 15 i = 0