y-iny=x^2+1

解答

y - in y = x^{2} + 1

无解

求解步骤

y - in y = x^{2} + 1

将

x^{2} + 1

改写成标准复数形式:

(x^{2} + 1) + 0 i

y - in y = (x^{2} + 1) + 0 i

复数仅在实部和虚部均相等时才相等改写为方程组:

[y = x^{2} + 1 - n y = 0]

[y = x^{2} + 1 - n y = 0] : 无解

无解

(a + b + 3) + (8 + b) i = 2 a + (3 a - b) i

(x + 1) + 6 y i = 4 + 24 i

s i \frac{159}{100} = a, b c

6 i - 2 j = a (i - j) + b (i + j)

so l v e f or z, ba rz = i z