(9-8i)-6=x-(2+yi)

解答

(9 - 8 i) - 6 = x - (2 + y i)

x = 5, y = 8

求解步骤

(9 - 8 i) - 6 = x - (2 + y i)

将

(9 - 8 i) - 6

改写成标准复数形式:

3 - 8 i

3 - 8 i = x - (2 + y i)

将

x - (2 + y i)

改写成标准复数形式:

(x - 2) - y i

3 - 8 i = (x - 2) - y i

复数仅在实部和虚部均相等时才相等改写为方程组:

[3 = x - 2 - 8 = - y]

[3 = x - 2 - 8 = - y] : x = 5, y = 8

x = 5, y = 8

(x + i y) (4 i) = 8

\frac{1285}{8} - 60 i = 1 0^{6} M^{2}

x + y i = (1 - i)^{2}

\frac{1 + z}{1 - z} = 8 i - 5

\frac{1 + 2 z}{3 + 2 z} = i