9^{x+1}=27^{x-1}

Lösung

9^{x + 1} = 2 7^{x - 1}

x = 5

Schritte zur Lösung

9^{x + 1} = 2 7^{x - 1}

Wende Exponentenregel an

2 (x + 1) = 3 (x - 1)

Löse

2 (x + 1) = 3 (x - 1) : x = 5

x = 5

4^{2 x - 1} = \frac{1}{64}

e^{- 4680 t} = \frac{1}{3}

7^{x} = 115

e^{x - 1} - 1 = 0

3 \cdot 2^{x} = 2 \cdot 3^{x}