81^{2x+1}=9^{5x-1}

Lösung

8 1^{2 x + 1} = 9^{5 x - 1}

x = 3

Schritte zur Lösung

8 1^{2 x + 1} = 9^{5 x - 1}

Wende Exponentenregel an

2 (2 x + 1) = 5 x - 1

Löse

2 (2 x + 1) = 5 x - 1 : x = 3

x = 3

2 \times 4^{x} = 2

2^{13 x} = 8

3^{2 x} = 2 7^{x + 1}

e^{x + 2} = e

e^{x} = e - 1