faktorisieren x^3-9

Lösung

faktorisieren completely

x^{3} - 9

(x - 39) (x^{2} + 39 x + 3 9^{2})

Schritte zur Lösung

x^{3} - 9

Wende Radikal Regel an:

a = (a)^{2}

9 = (39)^{3}

= x^{3} - (39)^{3}

Wende Formel zur Differenz von dritten Potenzen an:

x^{3} - y^{3} = (x - y) (x^{2} + x y + y^{2})

x^{3} - (39)^{3} = (x - 39) (x^{2} + 39 x + (39)^{2})

= (x - 39) (x^{2} + 39 x + (39)^{2})

(39)^{2} = 9^{\frac{2}{3}}

= (x - 39) (x^{2} + 39 x + 9^{\frac{2}{3}})

9^{\frac{2}{3}} = 3 9^{2}

= (x - 39) (x^{2} + 39 x + 3 9^{2})

so l v e f or A, b 2 A = \frac{1}{2} h (b_{1} + b_{2})

so l v e f or x, e^{l n (x^{2})} - 16 = 0

so l v e f or r, V = \frac{1}{3 p i r ^{2} h}

so l v e f or t, - lo g_{10} (12) = - (\frac{( lo g _{10} ( 2 ) )}{5.1}) t

s im pl i f y \frac{( - 75 )}{( - 72 )}